event | round | table | player one | result | player two |
Grand Prix Quebec City 2013 | 4 | 87 | Rowe, Jonathan (1820) | Won 2-1 | Huang, Hao-Shan (1845) |
Grand Prix Cleveland 2019 | 10 | 86 | Rowe, Jonathan (1863) | Won 2-1 | Huang, Hao-Shan (1755) |
Grand Prix Cleveland 2019 | 13 | 104 | Rowe, Jonathan (1878) | Lost 0-2 | Huang, Hao-Shan (1776) |